Halla la ordenada y1 en la parábola de la abcisa dada y calcula las coordenadas del simétrico de este punto en la parábola.

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y=-3x^{2}-6x-1

x1 = -4

Calculamos y1 sustituyendo x1 en la ecuación: y1 = -25

Esta es también la ordenada del simétrico: ys = -25

xs = x1 - 2·(x1 - x_eje) = -b/a - x1

xs = 2

y=x^{2}-4x+5

x1 = 2

y1 = ...

ys = ...

xs = ...

y=2x^{2}+4x+4

x1 = 2

y1 = ...

ys = ...

xs = ...

y=-x^{2}-4x-6

x1 = -2

y1 = ...

ys = ...

xs = ...

y=-3x^{2}-18x-25

x1 = -5

y1 = ...

ys = ...

xs = ...

y=2x^{2}-12x+19

x1 = 3

y1 = ...

ys = ...

xs = ...

y=-2x^{2}+2

x1 = -1

y1 = ...

ys = ...

xs = ...

y=-x^{2}-1

x1 = -5

y1 = ...

ys = ...

xs = ...

y=2x^{2}-4x+2

x1 = 0

y1 = ...

ys = ...

xs = ...

y=x^{2}-4x+4

x1 = -3

y1 = ...

ys = ...

xs = ...

y=2x^{2}-12x+16

x1 = -2

y1 = ...

ys = ...

xs = ...

y=-x^{2}+2x+1

x1 = 4

y1 = ...

ys = ...

xs = ...

y=-2x^{2}+2

x1 = 0

y1 = ...

ys = ...

xs = ...

y=-2x^{2}+8x-9

x1 = 5

y1 = ...

ys = ...

xs = ...

y=-2x^{2}

x1 = 4

y1 = ...

ys = ...

xs = ...

y=-3x^{2}-18x-26

x1 = -2

y1 = ...

ys = ...

xs = ...

y=3x^{2}-12x+11

x1 = 4

y1 = ...

ys = ...

xs = ...

y=x^{2}+6x+10

x1 = -5

y1 = ...

ys = ...

xs = ...

y=-x^{2}+2x-1

x1 = -3

y1 = ...

ys = ...

xs = ...

y=x^{2}-4x+6

x1 = 1

y1 = ...

ys = ...

xs = ...

y=-2x^{2}+12x-19

x1 = -4

y1 = ...

ys = ...

xs = ...

y=-x^{2}+6x-7

x1 = -5

y1 = ...

ys = ...

xs = ...

y=x^{2}-4x+6

x1 = -2

y1 = ...

ys = ...

xs = ...

y=-x^{2}+2

x1 = 3

y1 = ...

ys = ...

xs = ...