| \frac{-5}{x}+\frac{x-10}{x^2-2x}-\frac{16x}{x^2-12x+20}=\frac{-20}{x-10} | \frac{1}{x^2+x+1}+\frac{x^2+2}{x^3-1}=\frac{1}{x-1} |
| \frac{2x+4}{x^2-1}+\frac{x+2}{x^2-3x+2}=\frac{3x+6}{x^2-x-2} | \frac{-4}{x}+\frac{x-4}{x^2-x}-\frac{9x}{x^2-5x+4}=\frac{-12}{x-4} |
| \frac{-2}{x}+\frac{x-8}{x^2-4x}-\frac{x}{x^2-12x+32}=\frac{-2}{x-8} | \frac{3}{x}+\frac{x+6}{x^2-2x}+\frac{x}{x^2+4x-12}=\frac{5x+24}{x^2+4x-12} |
| \frac{1}{x^4+x^2+1}+\frac{x^4+2}{x^6-1}=\frac{1}{x^2-1} | \frac{5}{x}+\frac{x+25}{x^2-5x}+\frac{x}{x^2+20x-125}=\frac{7x+150}{x^2+20x-125} |
| \frac{1}{4x^4+2x^2+1}+\frac{4x^4+2}{8x^6-1}=\frac{1}{2x^2-1} | \frac{1}{x^4+x^3+x^2+x+1}+\frac{x^4+x^3+x^2+2}{x^5-1}=\frac{1}{x-1} |
| \frac{1}{x^4+x^3+2x^2+x+1}-\frac{2}{x^4+x^2+1}=\frac{-1}{(x^2-x+1)(x^2+1)} | \frac{2}{x}+\frac{x+4}{x^2-2x}+\frac{x}{x^2+2x-8}=\frac{4x+12}{x^2+2x-8} |