| \frac{1}{x^2+x+1}+\frac{x^2+2}{x^3-1}=\frac{1}{x-1} | \frac{1}{x^4+x^3+2x^2+x+1}-\frac{2}{x^4+x^2+1}=\frac{-1}{(x^2-x+1)(x^2+1)} |
| \frac{4}{x}+\frac{x+8}{x^2-2x}-\frac{25x}{x^2+6x-16}=\frac{-20}{x+8} | \frac{1}{4x^4+2x^2+1}+\frac{4x^4+2}{8x^6-1}=\frac{1}{2x^2-1} |
| \frac{1}{x}+\frac{x+3}{x^2-3x}+\frac{x}{x^2-9}=\frac{3x+6}{x^2-9} | \frac{-2}{x}+\frac{x-4}{x^2-2x}+\frac{x}{x^2-6x+8}=\frac{4}{x^2-6x+8} |
| \frac{-5}{x}+\frac{x-25}{x^2-5x}-\frac{16x}{x^2-30x+125}=\frac{-20}{x-25} | \frac{2}{x}+\frac{x+10}{x^2-5x}+\frac{x}{x^2+5x-50}=\frac{4x+30}{x^2+5x-50} |
| \frac{2x+4}{x^2-1}+\frac{x+2}{x^2-3x+2}=\frac{3x+6}{x^2-x-2} | \frac{1}{x^4+x^3+x^2+x+1}+\frac{x^4+x^3+x^2+2}{x^5-1}=\frac{1}{x-1} |
| \frac{-4}{x}+\frac{x-16}{x^2-4x}-\frac{9x}{x^2-20x+64}=\frac{-12}{x-16} | \frac{1}{x^4+x^2+1}+\frac{x^4+2}{x^6-1}=\frac{1}{x^2-1} |